Q
[tex] \\ [/tex]
[tex]{{ \huge\int}^{p}_1}{ \sf \: 3x(x + \frac{2}{3} )} \: \sf dx = 78. \: maka \: nilai - 2p = ..[/tex]
[tex] \\ [/tex]
No ngsl ,trmksih
[tex] \\ [/tex]
[tex]{{ \huge\int}^{p}_1}{ \sf \: 3x(x + \frac{2}{3} )} \: \sf dx = 78. \: maka \: nilai - 2p = ..[/tex]
[tex] \\ [/tex]
No ngsl ,trmksih
Penjelasan dengan langkah-langkah:
p
| 3x(x + ⅔)dx = 78
1
p
[x³ + x²] = 78
1
p³ + p² - (1³ + 1²) = 78
p²(p + 1) - 2 = 78
p² = 80
p = √80
p = 4√5
p + 1 = 5
p = 4